Question
A thermodynamic process begins at $1.2 \times 10^6 \textrm{ N/m}^2$ and 5 L. The state then changes to $1.2 \times 10^6 \textrm{ N/m}^2$ and 2 L. Next it becomes $2.2 \times 10^6 \textrm{ N/m}^2$ and 2 L. The next change is $2.2 \times 10^6 \textrm{ N/m}^2$ and 5 L. Finally, the system ends at $1.0 \times 10^6 \textrm{ N/m}^2$ and 5 L.
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(d)

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