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A thermodynamic process begins at $1.2 \times 10^6 \textrm{ N/m}^2$ and 5 L. The state then changes to $1.2 \times 10^6 \textrm{ N/m}^2$ and 2 L. Next it becomes $2.2 \times 10^6 \textrm{ N/m}^2$ and 2 L. The next change is $2.2 \times 10^6 \textrm{ N/m}^2$ and 5 L. Finally, the system ends at $1.0 \times 10^6 \textrm{ N/m}^2$ and 5 L.
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<b>Figure 15.43</b>
Figure 15.43
Question by OpenStax is licensed under CC BY 4.0.
Final Answer

(d)

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OpenStax College Physics Solution, Chapter 15, Problem 9 (Test Prep for AP® Courses) (1:24)

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Video Transcript
This is College Physics Answers with Shaun Dychko. A thermodynamic process begins at 1.2 times 10 to the 6 newtons per square meter in pressure and 5 liters. And so that's going to be this point here and the state then changes to the same pressure and so it’s going to go horizontally but to a smaller volume to two liters. So this is 2 liters and this is 5 liters and then that it stays at two liters and increases its pressure to 2.2 times 10 to the 6 newtons per square meter. So let’s label this as 1.2 times 10 to the 6 and up here it's gonna be 2.2 times 10 to the 6. So moves up to here and then it goes at the same pressure 2.2, it goes to 5 liters and so it moved here and then finally it’s ends at 1 point 0 times 10 to the 6 newtons per square meter but staying at 5 liters and so it passes point C because point C was 1.2 times 10 to the 6 and it ends at 1 point 0 times 10 to the 6 newtons per square meter. There we go, the answer is D, CFABD.